The general solution of the equation tan -tan - - -2- -2is given by -2n- n-

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General Solution of tan theta = tan alpha

The general s...

Question

The general solution of the equation $tan θ = tan α, \forall α \in (- \frac{π}{2}, \frac{π}{2})$
is given by $θ = 2 n π + α, n \in Z .$

True

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False

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If the general solution of the equation tan 3 θ = - 1, is given by θ = \frac{n π}{3} - α, where n \in Z and α \in (0, \frac{π}{6}], then α equals

cos θ = cos α

θ = n π \pm α, n \in Z .

If the general solution of the equation tan 3 θ = - 1, is given by θ = \frac{n π}{3} - α, where n \in Z and α \in (0, \frac{π}{6}], then α equals

T h e g e n e r a l s o l u t i o n o f t h e e q u a t i o n sin θ = sin α i s g i v e n b y θ = n π + {(- 1)}^{n} α, n \in Z .

\begin{matrix} T r i g o n o m e t r i c E q u a t i o n s & G e n e r a l S o l u t i o n s 1. s i n^{2} θ = s i n^{2} x & A . 2 n π \pm α 2. c o s^{2} θ = c o s^{2} x & B . n π + (- 1)^{n} α 3. t a n^{2} θ = t a n^{2} x & C . n π \pm α \end{matrix}

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