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Question

The general solution of the inequality 912(x+3)<1 and 5x928 is

A
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B
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C
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D
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Solution

The correct option is D
912(x+3)<1
102(x+3)<0
5(x+3)<0
0x+35
3<x2...(1)

Now,
5x928
10x916
1x25...(2)

From (1) and (2)
=

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