The general solution of the trignometric equation ${tan}^{2} θ = 1$ is:

θ = n π \pm \frac{π}{3}, n \in Z

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θ = n π \pm \frac{π}{6}, n \in Z

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θ = n π \pm \frac{π}{4}, n \in Z

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θ = n π, n \in Z

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Solution

The correct option is B $θ = n π \pm \frac{π}{4}, n \in Z$
Let ${tan}^{2} θ = tan α$
$\Rightarrow θ = n π \pm α$
$\Rightarrow {tan}^{2} θ = 1$
$\Rightarrow {tan}^{2} θ = {tan}^{2} \frac{π}{4}$
$\Rightarrow θ = n π \pm \frac{π}{4}$

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The value of $θ$ for which the system has nontrivial solution is

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The general solution of the trignometric equation tan2θ=1 is:

The correct option is B θ=nπ±π4,n∈ZLet tan2θ=tanα⇒θ=nπ±α⇒tan2θ=1⇒tan2θ=tan2π4⇒θ=nπ±π4

The general solution of the trignometric equation ${tan}^{2} θ = 1$ is:

The correct option is B $θ = n π \pm \frac{π}{4}, n \in Z$
Let ${tan}^{2} θ = tan α$
$\Rightarrow θ = n π \pm α$
$\Rightarrow {tan}^{2} θ = 1$
$\Rightarrow {tan}^{2} θ = {tan}^{2} \frac{π}{4}$
$\Rightarrow θ = n π \pm \frac{π}{4}$