CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

The general solution(s) of cos22xsin2x=0 can be

A
(2n+1)π6,nZ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(2n+1)π4,nZ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(2n+1)π2,nZ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
(2n+1)π,nZ
No worries! We‘ve got your back. Try BYJU‘S free classes today!