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Question

The general solutions for the equation cos4x=5+14 is

A
x=nπ±π20,nZ
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B
x=nπ2±π40,nZ
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C
x=nπ4±π20,nZ
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D
x=nπ2±π20,nZ
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Solution

The correct option is D x=nπ2±π20,nZ
cos4x=5+14=cos36
cos4x=cosπ5
4x=2nπ±π5,nZ
x=nπ2±π20,nZ

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