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Question

The general value of e is given by

A
ei(π2+2nπ)nϵ1
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B
e(π2+2nπ)nϵ1
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C
ei(π2+2nπ)nϵ1
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D
None of these
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Solution

The correct option is B e(π2+2nπ)nϵ1
e=eι0=ecos2nπ+ιsin2nπ
eι=ecosπ2+ιsinπ2
eι=ecos(2nπ+π2)+ιsin(2nπ+π2)


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