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Question


The general value of x for the equation 9cosx2.3cosx+1=0

A
nπ
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B
nπ2
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C
2nπ
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D
(2n+1)π2
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Solution

The correct option is D (2n+1)π2
take 3cosx=t
we get
t22t+1=0
t=1
so 3cosx=1
cosx=0
x=(2n+1)π2

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