The general value of - in the equation cos-1-2- tan-1 is

The correct option is D Here θ lies in the 4^th quadrant. ∴θ = 2π π/4 = 7π/4 Now considering the equation, cosθ = cos7π/4 ⇒ General value of θ = 2nπ±7π/4, ...

151

You visited us 151 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

General Solution of cos theta = cos alpha

The general v...

Question

The general value of θ in the equation $cos θ = \frac{1}{\sqrt{2}}, tan θ = - 1$ is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
Here $θ$ lies in the $4^{t h}$ quadrant.
$∴ θ = 2 π - \frac{π}{4} = \frac{7 π}{4}$
Now considering the equation,
$cos θ = cos \frac{7 π}{4}$
$\Rightarrow$ General value of $θ = 2 n π \pm \frac{7 π}{4}, n \in I$

Suggest Corrections

Similar questions

Q. Find the most general value of

θ

satisfying the equation

tan θ = - 1

and

cos θ = \frac{1}{\sqrt{2}}

Q. The most general value of

θ

satisfying the equations

tan θ = - 1

and

cos θ = \frac{1}{\sqrt{2}}

Q. The most general value of

θ

satisfying both the equations

s i n θ = \frac{1}{2}, t a n θ = \frac{1}{\sqrt{3}} i s (n ϵ Z)

Q. If

\frac{1}{6} sin θ, cos θ

and

tan θ

are in GP, then the general value of

θ

Q. The most general solution of the equations

tan θ = - 1, cos θ = \frac{1}{\sqrt{2}}

Join BYJU'S Learning Program

The general value of θ in the equation cosθ=1√2,tanθ=−1 is

The correct option is B Here θ lies in the 4th quadrant. ∴θ=2π−π4=7π4 Now considering the equation, cosθ=cos7π4 ⇒ General value of θ=2nπ±7π4,n∈I

The general value of θ in the equation $cos θ = \frac{1}{\sqrt{2}}, tan θ = - 1$ is

The correct option is B
Here $θ$ lies in the $4^{t h}$ quadrant.
$∴ θ = 2 π - \frac{π}{4} = \frac{7 π}{4}$
Now considering the equation,
$cos θ = cos \frac{7 π}{4}$
$\Rightarrow$ General value of $θ = 2 n π \pm \frac{7 π}{4}, n \in I$