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Question

The general value of θ satisfying both sinθ=12 and tanθ=13 is:

A
2nπ
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B
2nπ+7π/6
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C
nπ+π/4
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D
2nπ+π/4
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Solution

The correct option is B 2nπ+7π/6
Let us first find out θ lying between 0 and 360o.
Since sinθ=12θ=210o or 330o
and tanθ=13θ=30o or 210o
Hence θ=210o of 7π6 is the value satisfying both.
The general value of θ=(2nπ+7π6),nϵI
Hence (B) is the correct answer.

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