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Question

The general value of θ satisfying the equation tan2θ+sec2θ=1 is___

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Solution

tan2θ+sec2θ=1
t2+1+t21t2=1,wheret=tanθ
or t2(t23)=0
or tanθ=0,±3
θ=nπ and θ=nπ±π3,nZ


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