Question

The geometrical shape of ${BF}_3$ and ______ is same.

• A. $BeC{l}_2$
• B. $N{H}_3$
• C. $PC{l}_5$
• D. none of these

Answer 1

The correct option is B $N{H}_3$

$N{H}_3$ has a lone pair of electrons on the central Nitrogen with 3 bonded hydrogens. Therefore hybridization is $s{p}^3$. The lone pair takes up space and causes the molecule to adopt a non-planar geometry. The shape of a molecule is trigonal pyramidal.

The central Boron in $B{F}_3$ has no lone pair and three bonded fluorines. Therefore hybridization is $s{p}^2$. and shape is trigonal planar. It gets to be planar as this is the best geometry to keep the fluorines as far away from each other as possible. Hence the statement is false.