Question

The geometry of $Ni(CO{)}_4$ and $Ni(PP{h}_3{)}_{2}C{l}_2$ are :

• A. both square planar
• B. tetrahedral and square planar, respectively
• C. both tetrahedral
• D. square planar and tetrahedral, respectively

Answer 1

The correct option is B tetrahedral and square planar, respectively

In $Ni(CO{)}_4$ the four carbonyl carbons are at the four corners of regular tetrahedron thus it has tetrahedral structure and in $Ni(PP{h}_3{)}_{2}C{l}_2$

the ligands are at the corners of a square. Hence, its geometry is square planar.