Question

The geometry of $\left[Ni\right(CO{)}_4]$ and $\left[NiC{l}_2\right(PP{h}_3{)}_3]$ are :

• A. both square planar.
• B. tetrahedral and square planar respectively.
• C. both are tetrahedral.
• D. square planar and tetrahedral respectively.

Answer 1

The correct option is C both are tetrahedral.

In $\left[Ni\right(CO{)}_4]$ and $\left[NiC{l}_2\right(PP{h}_3{)}_3]$, the central metal atom/ion undergoes $s{p}^3$ hybridization to form tetrahedral geometry.

Nickel is at the centre and four ligands are at the corners of a tetrahedron.

Hence, the correct option is C.