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Question

The geometry of [Ni(CO)4] and [NiCl4]2 are respectively:

A
Both are square planar
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B
Tetrahedral and square planar
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C
Both are tetrahedral
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D
Square planar and tetrahedral
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Solution

The correct option is C Both are tetrahedral
[Ni(CO)4] and [NiCl4]2
are both tetrahedral.

Using VBT, in the case of [Ni(CO)4],
28Ni[Ar]3d84s2

Since, CO (carbonyl) is a strong and neutral ligand
it pairs up `3d` orbitals to give [Ar]3d104so configuration. 4s and 4p orbitals participate in hybridisation shows sp3 hybridisation.

Using VBT, in the case of [NiCl4]2,
Ni2+[Ar]3d84s0
Cl is a weak ligand.
no pairing occurs and it will show sp3 hybridisation and thus the geometry will be tetrahedral.

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