The Gibbs energy for the decomposition of Al2O3 at 500oC is as follows- 23Al2O3-43Al-O2-rG-96kJThe voltage needed for the electrolytic reduction of aluminium oxide Al2O3 at 500oC is at least-

The correct option is A 2.5V #916;G= #8722;nF Eon=4 #160;For decomposition of Al_2O_3 , 4 moles of electrons are transferred. F=Farada ...

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Gibb's Free Energy

The Gibbs ene...

Question

The Gibbs energy for the decomposition of ${A l}_{2} O_{3}$ at $500^{o} C$ is as follows:
$\frac{2}{3} {A l}_{2} O_{3} \to \frac{4}{3} A l + O_{2}; Δ_{r} G = + 96 k J$
The voltage needed for the electrolytic reduction of aluminium oxide ( ${A l}_{2} O_{3}$ ) at $500^{o} C$ is at least:

- 4.5 V

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- 3.0 V

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- 2.5 V

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- 5.0 V

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Similar questions

{A l}_{2} O_{3}

500^{o} C

\frac{2}{3} {A l}_{2} O_{3} \to \frac{4}{3} A l + O_{2}; Δ_{r} G = + 960 k J {m o l}^{- 1}

({A l}_{2} O_{3})

500^{o} C

{A l}_{2} O_{3}

500^{o} C

\frac{2}{3} {A l}_{2} O_{3} ⟶ \frac{4}{3} A l + O_{2};

Δ G = + 960 k J

{A l}_{2} O_{3}

500^{o} C

A l_{2} O_{3}

500^{o} C

\frac{2}{3} A l_{2} O_{3} \to \frac{4}{3} A l + O_{2}, Δ_{r} G = + 966 k J m {o l}^{- 1}

A l_{2} O_{3}

500^{o} C

{A I}_{2} O_{3}

500^{0} C

\frac{2}{3} {A I}_{2} O_{3} ⟶ \frac{4}{3} A I + O_{2}; △_{r} G = + 966 k J {m o l}^{- 1}

{A I}_{2} O_{3}

500^{0} C

A l_{2} O_{3}

500^{0} C

\frac{2}{3} A l_{2} O_{3} \to \frac{4}{3} A l + O_{2}

Δ_{r x n} G = + 960 k J m o l^{- 1}

(A l_{2} O_{3})

500^{o} C

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