CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The given apparatus shows a heavy piston supported by gas trapped in a cylinder. The cross-sectional area of the piston is 4.0×104m2. The pressure of the gas inside the cylinder is 1.5×105 Pa and atmospheric pressure is 1.0×105 Pa. Find the mass of the piston (Take g = 10 m s2)
315610.png

A
1 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2 kg
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2 kg
Force acting on the piston is balanced.
Upward force =PA
Downward force =P0A+mg
equating the two:
mg=A(PP0)
m=Ag(PP0)=410410(0.5105)=2kg
Hence option B is correct.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The First Law of Thermodynamics
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon