Question

The given circuit has two ideal diodes connected as shown in figure. The current flowing through $R_1$ will be

• A. 2.5 $A$
• B. 10.0 $A$
• C. 1.43 $A$
• D. 3.13 $A$

Answer 1

The correct option is A 2.5 $A$

We know that a diode only conducts in forward biased condition. In the given circuit, the diode $D_1$ is in reverse bias, so it will block the current and diode $D_2$is in forward bias, so it will pass the current. So now $R_1$and $R_3$ will be in series and since diode is ideal, it will not have any resistance. Hence, total resistance
$R_{eq}=R_1+R_3$
$i=\frac{v}{R_1+R_3}=\frac{10}{2+2}=2.5A$