The correct option is D
d a b c
In isochoric process, volume remain constant. So, its graph will be a straight line parallel to the pressure axis which is d.
In isobaric process, pressure remain constant. So, its graph will be a straight line parallel to the volume axis which is a.
The equation of isothermal process is PV=constant
So, the graph of this process will be a rectangular hyperbola, a second degree curve.
The equation of adiabatic process is PVγ=constant
So, the graph of this process will be a curve whose degree will be greater than two.
So, the graphs of these processes will be as stated below.
a → Isobaric, b → Isothermal, c → Adiabatic, d → Isochoric
Hence, (D) is the correct answer.