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B
NOR gate
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C
NOT gate
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D
AND gate
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Solution
The correct option is B NOR gate Y1=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯A+B Y2=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯Y1+Y1=¯¯¯¯¯Y1=A+B Y=¯¯¯¯¯Y2=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯A+B Thus the circuit is equivalent to NOR gate.