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Question

The given expression is (x+x31)5+(xx31)5 is a

A
polynomial of fractional degree.
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B
polynomial of degree 7.
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C
polynomial with integer degree.
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D
not a polynomial.
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Solution

The correct option is C polynomial with integer degree.
The given expression is (x+x31)5+(xx31)5 we know that
(x+a)n+(xa)n=2[nC0xn+nC2xn2a2+nC4xn4a4+]
Therefore the given expression is equal to 2[5C0x5+5C2x3(x31)+5C4x(x31)2].
Maximum power of x involved here is 7.
Also only + ve integral powers of x are involved.
Therefore, the given expression is a polynomial of degree 7.

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