The given fig is drawn using more than one triangle:
$∠ D A B + ∠ A B C + ∠ B C D + ∠ C D A$

Open in App

Solution

The figure is drawn using two triangles which forms a quadrilateral
As we know that
sum of angles in a quadrilateral is $360^{\circ}$
$⟹ ∠ D A B + ∠ A B C + ∠ B C D + ∠ C D A = 360^{\circ}$

Suggest Corrections

Similar questions

△ D A B ≅ △ B C D

A^{T} = B C D; B^{T} = C D A; C^{T} = D A B

D^{T} = A B C

M = A B C D

M^{2016}

a, b, c, d

a + b + c + d = 2

\frac{1}{a b c} + \frac{1}{b c d} + \frac{1}{c d a} + \frac{1}{d a b}

In the given figure, which congruence rule can be used to prove that $△$ ABC $≅$ $△$ CDA?

∣ ∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 & a & a^{2} & a^{3} + b c d 1 & b & b^{2} & b^{3} + c d a 1 & c & c^{2} & c^{3} + a b d 1 & d & d^{2} & d^{3} + a b c \end{matrix} ∣ ∣ ∣ ∣ ∣ ∣

Join BYJU'S Learning Program