Question

The given figure is a cross section which consists of a rectangle and two semicircles. From the information given, find the area of the cross section.

• A. 138 $c{m}^2$
• B. 238 $c{m}^2$
• C. 338 $c{m}^2$
• D. 438 $c{m}^2$

Answer 1

Answer: (B)

238 $c{m}^2$

Given: Length of the rectangle = 14 cm
breadth = 6 cm
Area of the cross section = Area of the 2 semicircles + area of the rectangle
= $2\left[\frac{\pi r^2}{2}\right]+lb$
= $[\frac{22}{7}\times 7^2+14\times 6]$
= 154 + 84
= 238 $c{m}^2$