The given figure is made up of a square and two isosceles triangles. What is the measure of the angle marked $^{'} m^{'}$ ?

105^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

95^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

135^{o}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

85^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $135^{o}$
Since ABDE is a square.
So, all its angles will be 90 degree.
Since BCD and DEF are isosceles right angled triangle.
So, their angles are 45 - 90 - 45 degrees.
Now at center D,
90 + 90 + 45 + $m$ = 360
$m$ = 135.

Suggest Corrections

Similar questions

Q. Two angles of a triangle measure

15^{o}

and

85^{o}

. What is the measure of the third angle ?

What will be the Perimeter of the isosceles right-angled $△$ LON in the given figure?
(Given: KLOJ is a square)

As both the set-squares have right angle at one corner, the set-square that is the isosceles triangle has two angles measuring ______ each and the set square that is the scalene triangle has two angles measuring ______and ______.

Q. The pyramid in Figure 3 is composed of a square base of area

16

and four isosceles triangles, in which each base angle measures

60^{o}

. Calculate the volume of the pyramid.

Q. In given figure

□

PQRS is an Isosceles trapezium.Side PQ

∥

side SR and

△

RQE is an equilateral triangle; find the measures of all the angles of the trapezium.

Join BYJU'S Learning Program

The given figure is made up of a square and two isosceles triangles. What is the measure of the angle marked ′m′ ?

The correct option is B 135oSince ABDE is a square.So, all its angles will be 90 degree.Since BCD and DEF are isosceles right angled triangle. So, their angles are 45 - 90 - 45 degrees.Now at center D, 90 + 90 + 45 + m = 360m = 135.

The given figure is made up of a square and two isosceles triangles. What is the measure of the angle marked $^{'} m^{'}$ ?

The correct option is B $135^{o}$
Since ABDE is a square.
So, all its angles will be 90 degree.
Since BCD and DEF are isosceles right angled triangle.
So, their angles are 45 - 90 - 45 degrees.
Now at center D,
90 + 90 + 45 + $m$ = 360
$m$ = 135.