Question

The given figure represents the graph of?

• A. $f\left(x\right)=x$
• B. $f\left(x\right)=\frac{1}{x}$
• C. $f\left(x\right)=\frac{1}{x-2}$
• D. $f\left(x\right)=\frac{1}{x+2}$

Answer 1

The correct option is B $f\left(x\right)=\frac{1}{x}$

The graph tends to infinity as x tends to zero . This implies that denominator must be tending to zero when x tends to zero. This takes place only in b option i.e. $f\left(x\right)=\frac{1}{x}$.

We can also observe from the graph that the function is an odd function , i.e. the graph is symmetric about origin.

i.e. $f\left(x\right)=-f(-x)$