The given figure shows a block and tackle system of pulleys used to lift a load. When the load is pulled up by a distance 1 m, how far does the effort end move?

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Solution

The correct option is D
4m

Number of strands supporting the load = number of pulleys = 4

M.A = $\frac{L o a d}{E f f o r t}$ = $\frac{4 T}{T}$ = 4

L = 4T and E = T

If $d_{L}$ = d and $d_{E}$ = nd

So, if $d_{L}$ = 1m then $d_{E}$ = 4 $\times$ 1 = 4m

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Similar questions

The given figure shows a block and tackle system of pulleys used to lift a load. When the load pulled up by a distance 1m, how much do the effort end move?

Q. Fig 3.40 shows a block and tackle system of pulleys used to lift a load.
When load is pulled up be a distance

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In fig shows a block and tackle system of pulleys used to lift a load .

(a) How many strands of tackle are supporting the load ?

(b) Draw arrows to represent tension T in each strand.

(d) When load is pulled up by a distance 1 m, how far does the effort end move ?

(e) How much effort is needed to lift a load of 100 N ?

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, how far does the effort end move?

A block and tackle system of 5 pulleys consist of 3 pulleys in the upper block and 2 pulleys in the lower block. If the load is raised by 1 m, through what distance will effort move?

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The given figure shows a block and tackle system of pulleys used to lift a load. When the load is pulled up by a distance 1 m, how far does the effort end move?

The correct option is D 4m Number of strands supporting the load = number of pulleys = 4 M.A = LoadEffort = 4TT = 4 L = 4T and E = T If dL = d and dE = nd So, if dL = 1m then dE = 4 × 1 = 4m

The correct option is D
4m

Number of strands supporting the load = number of pulleys = 4

M.A = $\frac{L o a d}{E f f o r t}$ = $\frac{4 T}{T}$ = 4

L = 4T and E = T

If $d_{L}$ = d and $d_{E}$ = nd

So, if $d_{L}$ = 1m then $d_{E}$ = 4 $\times$ 1 = 4m