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Question

The given figure shows a circuit diagram containing 12 cells, each of EMF 1.5 V and internal resistance 0.25Ω. Calculate the:

(a) total internal resistance.
(b) total EMF.
(c) reading shown by the ammeter.
(d) Current in 12Ω and 8Ω resistors.
[5 MARKS]


Solution

part a,b,c: Each 1 Mark
part d: 2 Marks

(a) Total internal resistance of 12 cells in series = 12 × 0.25 = 3Ω
(b) Total EMF = 12 × 1.5 = 18 V
(c) Reading shown by ammeter, I=ϵR+r=189+3=1812=1.5 A
(d) Potential difference across parallel circuit,
V=IR=1.5×6=9 V
[ Equivalent resistance of 4Ω, 8Ω and 12Ω = 6Ω]
Current in 12Ω resistor,
I=VR=912=0.75 A
Current in 8Ω resistor, I=VR=98=1.125 A

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