Question

The given figure shows a frame loaded with a single concentrated load P. The fixed-end moment developed at support A will be

• A. $\frac{PL}{3}$
• B. $\frac{PL}{4}$
• C. $\frac{PL}{6}$
• D. $\frac{PL}{8}$

Answer 1

The correct option is C $\frac{PL}{6}$

$\text{The eccentric load P can be replaced}$ $\text{by a load P and moment PL at the joint D.}$ $\text{The distribution factor for member AD, BD and CD will be}$ $\frac{1}{3}\text{for each.}$
$\therefore M_{DA}=\frac{PL}{3}$
$\text{Carry over factor for the beam AD is}\frac{1}{2}.$
$\therefore M_{AD}=\frac{PL}{6}$