Question

The given figure shows a network of currents. The current $i$ is

• A. 23 A
• B. 22 A
• C. 20 A
• D. 25 A

Answer 1

The correct option is A 23 A

Here, consider the above part of circuit as shown in figure and applying Kirchhoff's current law we obtain

$I_1+5-I_2=0$

$I_1=I_2-5$..................................................(1)

$I_2+15-I_3=0$

$I_2=I_3-15$..........................................(2)

$I_3+3-I_4=0$

$I_3=I_4-3$..........................................(3)

and $I_4-i-I_1=0$

$I_4=I_1+i$...............................................(4)

now using values from equations(2), (3) and (4) into (1)we get

$I_1=I_1+i-23$

$\therefore i=23$ A