The given figure shows a rectangle ABCD inscribed in a circle as shown alongside. If AB=28 cm and BC=21 cm, find the area of the shaded portion of the given figure.
A
374.5cm2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
274.5cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
174.5cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A374.5cm2 Diagonal AC passes through the centre of the circle. ∴AC is the diameter. Now, area of rectangle ABCD=AB×AC =28×21 =588cm2 In △ABC AC2=AB2+CB2 =282+212 =784+441 =1225 ⇒AC2=√1225 ⇒AC=35 cm ∴ radius =AC2 =352 =17.5 Area of the circle =πr2 =227×(17.5)2 =962.5cm2 Area of the shaded region = Area of the circle − Area of rectangle ABCD =962.5−588cm2 =374.5cm2