The given figure shows a siphon in action. The liquid flowing through the siphon has a density of $1.5 g / c c$ . Calculate the pressure difference between
(i) points $A$ and $D$
(ii) points $C$ and $B$

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Solution

Since point B & C are same horizontal level, hence according to Arrhenius law they are at same pressure and
$P_{D} - P_{A} = ϱ g h = 1500 \frac{k g}{m^{3}} \times 10 m / s^{2} \times 1.8 m$
= 27000 $

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The given figure shows a siphon in action. The liquid flowing through the siphon has a density of 1.5g/cc. Calculate the pressure difference between(i) points A and D(ii) points C and B

Since point B & C are same horizontal level, hence according to Arrhenius law they are at same pressure andPD−PA=ϱgh=1500kgm3×10m/s2×1.8m = 27000 $

The given figure shows a siphon in action. The liquid flowing through the siphon has a density of $1.5 g / c c$ . Calculate the pressure difference between
(i) points $A$ and $D$
(ii) points $C$ and $B$

Since point B & C are same horizontal level, hence according to Arrhenius law they are at same pressure and
$P_{D} - P_{A} = ϱ g h = 1500 \frac{k g}{m^{3}} \times 10 m / s^{2} \times 1.8 m$
= 27000 $