Question

The given figure shows a solid formed of a solid cube of side 40 cm and a solid cylinder of radius 20 cm and height 50 cm attached to the cubes as shown. Find the volume and the total surface area of the whole solid [Take $\pi =3.14$]

• A. $122700c{m}^3$ and $15880c{m}^2$
• B. $126800c{m}^3$ and $15880c{m}^2$
• C. $148900c{m}^3$ and $15880c{m}^2$
• D. $148800c{m}^3$ and $15880c{m}^2$

Answer 1

Answer: (B)

$126800c{m}^3$ and $15880c{m}^2$

Given: Side of the cube $=40cm$ and radius of the cylinder $=20cm$ and height of the cylinder $=50cm$

Volume of cube $=(side{)}^3$

$=(40{)}^3$

$=64000c{m}^3$

Volume of cylinder $=\pi r^{2}h$

$=3.14\times (20{)}^2\times 50$

$=62800c{m}^3$

So, total volume of solid $=64000+62800=126800c{m}^3$

Now, surface area of cube $=6(side{)}^2$

$=6(40{)}^2$

$=9600c{m}^2$

The surface area of cylinder $=2\pi rh$

$=3.14\times 20\times 50$

$=6280c{m}^2$

$\therefore$ Total surface area of solid $=9600+6280=15880c{m}^2$