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Question

The given figure shows a trapezium in which AB || DC and diagonal AC and BD intersect at point P. If AP : CP = 3:5 and area of APB is 27 m2, then the area of CPD is ___.


A

72 m2

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B

75 m2

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C

81 m2

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D

84 m2

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Solution

The correct option is B

75 m2


In ΔAPB and ΔCPD,

APB=CPD (vertically opposite angles)

PDC=PBA (alternate angles)

ΔAPB ΔCPD (by AA similarity criterion)

AP2CP2=ar(ΔAPB)ar(ΔCPD)

(Since the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.)

(APCP)2=ar(ΔAPB)ar(ΔCPD)

(35)2=27 m2ar(ΔCPD)

ar(ΔCPD)=27×259=75 m2


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