The given figure shows a weightless lever in equilibrium. Neglect friction at the fulcrum F.

Calculate the mechanical advantage for the given lever.

$\frac{E f f o r t a r m}{L o a d a r m}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\frac{l o a d a r m}{E f f o r t a r m}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{2 \times E f f o r t a r m}{L o a d a r m}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{E f f o r t a r m}{2 \times L o a d a r m}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$\frac{E f f o r t a r m}{L o a d a r m}$

The mechanical advantage (MA) of machine is the ratio of the resistance to overcome to the effort applied to the machine
$∴$ MA $= \frac{R e s i s t a n c e o v e r c o m e}{E f f o r t a p p l i e d}$
By the principle of moments, we have
Load $\times$ Load arm = Effort $\times$ Effort arm
or L $\times$ b = E $\times$ a, where a and b are the effort arm and the load arm respectively.
or $\frac{L}{E} = \frac{a}{b}$
i.e. MA of a lever $= \frac{E f f o r t a r m}{L o a d a r m}$

Suggest Corrections

Similar questions

Calculate the mechanical advantage of a lever whose effort arm is $50 c m$ and the load arm is $2 c m$ .

4

90 cm

Calculate the mechanical advantage of a lever in which the effort arm is 50 cm and the load arm is 2cm ___.

Join BYJU'S Learning Program