The given figure shows parallelogram ABCD points P and Q price at the side a b then

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The given figure shows parallelogram ABCD. Points P and Q trisect the side AB, then which of the following is correct?

The given figure shows parallelogram ABCD. Points P and Q trisects the side AB.
To prove: Area of $△$ DPQ = $\frac{1}{6}$ × Area of (parallelogram ABCD)

Q. The given figure shows a parallelogram ABCD. Point P and Q trisect the side AB. Show that : area (

Δ D P Q

) = area (BQC) =

\frac{1}{6} \times a r e a (/ /_{g m} A B C D)

Q. In given figure the side

A B

of a parallelogram

A B C D

is produced to any point

P

. A line through A and parallel to

C P

meets

C B

produced at

Q

and then parallelogram

P B Q R

is completed (see Fig). Show that:

a r e a (A B C D) = a r e a (P B Q R)

If the given figure shows parallelogram ABCD. Points P and Q trisect the side AB, then ____.

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The given figure shows parallelogram ABCD points P and Q price at the side a b then

Dear student, your question is incomplete. please recheck it and come back again. Thanks. ​​​​​​

Dear student,
your question is incomplete.
please recheck it and come back again.
Thanks.