(a) Speed=Distance travelledTime taken = Slope of distance-time graph
Since the slope of object B is the greatest, it is travelling the fastest.
(b) The three objects are never at the same point on the road as their graphs don't coincide simultaneously at any point.
(c) On the distance axis:
7 small boxes = 4 km
Therefore,1 small box =47km
Initially, object C is 4 blocks away from the origin.
Therefore, initial distance of object C from origin =4×47=167
Distance of object C from origin when B passes A =47×16=647
Distance covered by C=647−167=64−167=487=6.85 km
Hence, the total distance covered by C when B passes A is 6.85 km
(d) Distance covered by B at the time it passes C = 9 boxes
Distance traveled by B when it passes C =47×9=367=5.143 km
Hence, B has traveled a distance of 5.143 km when B passes C.