Question

The given figure shows the distance-time graphs of two trains, which start moving simultaneously in the same direction, from the graphs, find:

i) How much $B$ is ahead of $A$ when motion starts?

ii) What is the speed of $B$?

iii) When and where $A$ will catch $B$?

iv) What is the difference in speeds of $A$ and $B$?

Answer 1

b'1. B is 100 km ahead of A.

2. speed of B $=\frac{QR}{PR}=\frac{150-100}{2-0}=25Km/h$

3. A will catch B at point Q after 2hrs and at a distance of 150Km.

4. speed of A= $\frac{QS}{OS}=\frac{150-0}{2-0}=75Km/h$

speed of B =$25Km/h$

so, the difference is $50Km/h$

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