Question

The given figure shows the electric lines of force emerging from a charged body. If the electric field at $A$ and $B$ are $E_A$ and $E_B$ respectively and if the displacement between $A$ and $B$ is $r$, then

• A. $E_A>E_B$
• B. $E_A<E_B$
• C. $E_A=\frac{E_B}{r}$
• D. $E_A=\frac{E_B}{r^2}$

Answer 1

The correct option is A $E_A>E_B$

$\bullet$ Electric field intensity is proportional to the density of electric field lines.

$\bullet$ As we go from A to B, the density of electric field lines decreases(Refer Figure)

$\Rightarrow$ $E_A>E_B$

Hence, option $A$ is correct.

$\text{Note:}$ No use of $r$ in comparing the magnitudes of Electric fields at points A and B