The given figure shows the isotherms of a fixed mass of an ideal gas at three temperatures TA,TB and TC then
A
TA>TB>TC
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B
TA<TB<TC
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C
TB<TA<TC
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D
TA=TB=TC
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Solution
The correct option is BTA<TB<TC From the ideal gas equation, PV=nRT ⇒nRTV=P By drawing a straight line parallel to P - axis, value of 1V is fixed. Thus, P∝T
⇒PC>PB>PA ∴TC>TB>TA
OR
From the ideal gas equation, PV=nRT ⇒1V=PnRT Comparing with y=mx, m∝1T Slope of A> Slope of B> Slope of C Hence, TC>TB>TA