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Question

The given figure shows the isotherms of a fixed mass of an ideal gas at three temperatures TA,TB and TC then

A
TA>TB>TC
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B
TA<TB<TC
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C
TB<TA<TC
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D
TA=TB=TC
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Solution

The correct option is B TA<TB<TC
From the ideal gas equation,
PV=nRT
nRTV=P
By drawing a straight line parallel to P - axis, value of 1V is fixed.
Thus, P T

PC>PB>PA
TC>TB>TA


OR

From the ideal gas equation,
PV=nRT
1V=PnRT
Comparing with y=mx,
m1T
Slope of A> Slope of B> Slope of C
Hence, TC>TB>TA

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