Question

The given figure shows the path of two balls.

If path followed by the blue ball and the red ball is 2x-5y=4, and 3x-ky=6 respectively.


Determine the point of intersection of the path of the balls. Provided k=7.

• A. (0,2)
• B. (2,2)
• C. (0,0)
• D. (2,0)

Answer 1

The correct option is D (2,0)

Given 2x-5y=4 ...eq(1)
and 3x-7y=6 ...eq(2)
from eq(1), x= $\frac{4+5y}{2}$ ...eq(3)
substituting eq(3) in eq(2)
so, 3($\frac{4+5y}{2}$) - 7y = 6
$\therefore$ 12 +15y - 14y = 12
$\therefore$ y=0
putting the obtained value of y in eq(3)
x=$\frac{4+0}{2}$ = 2.
so the point of intersection is (2,0).