Question

The given image shows the number of bricks in each bag. All the bricks need to be arranged in piles of $10$.

(i) Are there the same number of bricks in each bag?
(ii) How many piles can be made?
(iii) How many bricks will be left loose?

• A. $\text{(i) Yes; (ii) 5 piles; (iii) 6 bricks}$
• B. $\text{(i) No; (ii) 5 piles; (iii) 8 bricks}$
• C. $\text{(i) No; (ii) 6 piles; (iii) 8 bricks}$
• D. $\text{(i) Yes; (ii) 7 piles; (iii) 7 bricks}$

Answer 1

The correct option is C $\text{(i) No; (ii) 6 piles; (iii) 8 bricks}$

There are $3$ rods and $7$ dots representing the number of bricks in bag $1$.
We know that $1$ rod $=10$ and $1$ dot $=1$ unit cube = 1
So, bag $1=37$
There are $2$ rods and $11$ dots representing the number of bricks in bag $2$.
$1$ rod $=10$ unit cubes. So here, $11$ dots $=11$ units cubes $=1$ rod and $1$ units cube
So, bag $2=31$
Therefore, we can say that bag $1$ has more bricks compared to bag $2$.
Total number of bricks $=37+31=68$

The total number of bricks are to be arranged in piles of $10$.
We can break down $68$ as $6$ tens and $8$ ones.
Therefore, we can conclude that $6$ piles will be made and $8$ bricks will be left loose.