The given polygon has 4 lines of symmetry and order of rotational symmetry is 4.

The adjacent sides of the polygon are not equal. Perimeter of the polygon is 24m. Given

one side length as 9 m, find the area of the polygon?

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Solution

The given polygon will be rectangle.

Perimeter = 24

2(a+b) = 24

b = 3

Area of the rectangle= (9)*(3)

= 27 $m^{2}$

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The given polygon has 4 lines of symmetry and order of rotational symmetry is 4. The adjacent sides of the polygon are not equal. Perimeter of the polygon is 24m. Given one side length as 9 m, find the area of the polygon?

The given polygon will be rectangle. Perimeter = 24 2(a+b) = 24 b = 3 Area of the rectangle= (9)*(3) = 27 m2

The given polygon has 4 lines of symmetry and order of rotational symmetry is 4.

The adjacent sides of the polygon are not equal. Perimeter of the polygon is 24m. Given

one side length as 9 m, find the area of the polygon?

The given polygon will be rectangle.

Perimeter = 24

2(a+b) = 24

b = 3

Area of the rectangle= (9)*(3)

= 27 $m^{2}$