Question

The given relation is $\frac{1}{\sin 10}-\frac{\sqrt{3}}{\cos 10}=2$

• A. True
• B. False

Answer 1

The correct option is B False

Given

$\frac{1}{\sin 10}-\frac{\sqrt{3}}{\cos 10}=2$

$\frac{\cos 10-\sqrt{3}\sin 10}{\sin 10\cos 10}=2$

$\cos 10-\sqrt{3}\sin 10=2\sin 10\cos 10$

$\frac{1}{2}\cos 10-\frac{\sqrt{3}}{2}\sin 10=\frac{1}{2}\sin 20$

$\sin \frac{\pi }{6}\cos 10-\sin 10\cos \frac{\pi }{6}=\frac{1}{2}\sin 20$

$⟹\sin (\frac{\pi }{6}-10)=\frac{1}{2}\sin 20$

This equation is not true.

So It is false.