Question

The given setup is in equilibrium and springs were in natural length before force was applied. If I have to replace the above setup by 1 block and 1 spring then what will be the spring constant of that new spring, such that the block is displaced by the same amount previously by the applied force.

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

The force on the block makes the block move right so the spring are elongated. The elongation will be same in both the springs. (That means they are in parallel and you know what to do in parallel but still lets have patience)

$F=K_1{X}_0+K_2{X}_0$

$F=(K_1+K_2)X_0$ ................(i)

Now replacing with are spring

$F=K{x}_0$ ...................(ii)

(i) = (ii)

$K_1+K_2=K$