Question

The given shelf is right angled at $A$ and $AB=AC=48$ inches. Find the area of the shelf.

• A. $1155sq$ in
• B. $1142sq$ in
• C. $1158sq$ in
• D. $1152sq$ in

Answer 1

The correct option is D $1152sq$ in

Area of a triangle $=\frac{1}{2}\times \text{base}\times \text{height}$
The given triangle is right angled at $A.$
Considering $AB$ as the base and AC as the corresponding height, we get:

Area of the shelf $=\frac{1}{2}\times AB\times AC$
$=\frac{1}{2}\times 48\times 48$
(Since $AB=AC=48$ in)
$=1152sq$ in
Hence, the area of the shelf is $1152sq$ in.