Question

The given table shows the distance covered by the plane during take off.

Distance "d" (in m)	$45$	$180$	$720$
TIme "t" ( in s)	$3$	$6$	$12$

Find the relationship between the average speed “s” of the plane and the time “t”.
Hint: $\text{Speed}=\frac{\text{Distance}}{\text{Time}}$

• A. $s=6t$
• B. $s=3t$
• C. $s=5t$
• D. $s=2.5t$

Answer 1

The correct option is C $s=5t$

Let’s tabulate to find the speed of the airplane at different positions.

Distance "d" (n m)	Time "t" (in s)	Average speed "s" (in m/s) $(s=\frac{d}{t})$	Ratio of speed to time $\frac{s}{t}$
$45$	$3$	$15$	$5$
$180$	$60$	$30$	$5$
$405$	$9$	$45$	$5$
$720$	$12$	$60$	$5$

From the table we can conclude:
$\frac{s}{t}=5$
$s=5t$