Question

The given table shows the distance traveled by two bikes in different instances. Find the distance between the two bikes after $18$ hours if they start from the same point and follow the same path.

	Time "" (in hr)	$2$	$5$	$7$
Bike A	Distance traveled "a" miles	$80$	$200$	$280$
Bike B	Distance traveled "b" miles	$102$	$255$	$357$

• A. $168km$
• B. $158km$
• C. $208km$
• D. $198km$

Answer 1

The correct option is D $198km$

For Bike A:

Distance traveled "a" miles	Time "t" (in hr)	Distance traveled per hour $\frac{a}{t}$
$80$	$2$	$\frac{80}{2}=40$
$200$	$5$	$\frac{200}{5}=40$
$280$	$7$	$\frac{280}{7}=40$

Hence , we have $\frac{a}{t}=40$
$a=40t$

For Bke B:

Distance traveled "b" miles	Time "t" (in hr)	Distance traveled per hour $\frac{b}{t}$
$102$	$2$	$\frac{102}{2}=51$
$255$	$5$	$\frac{255}{5}=51$
$357$	$7$	$\frac{357}{7}=51$

Hence , we have $\frac{b}{t}=51$
$b=51t$

Distance covered by bike A after 18 hours $=40\times 18=720km$
Distance covered by bike B after 18 hours $=51\times 18=918km$
Distance between bike A and bike B after $18$ hours $=918-720=198km$