Question

The given table shows the genetic code depicting the amino acids that correspond to mRNA codons. Each codon is read from $3^{\prime }$ (first nucleotide) to $5^{\prime }$ (third nucleotide). Find out the amino acid sequence that can be assembled from the mRNA associated with the given DNA strand.

DNA template strand: $5^{\prime }-GCGACATACACT-3^{\prime }$

• A. Ala - Cys - Met
• B. Arg - Cys - Met
• C. Ala - Thr - Tyr - Thr
• D. Ala - Thr - Tyr - Trp
• E. Arg - Thr - Tyr - Thr

Answer 1

The correct option is B Arg - Cys - Met

The mRNA sequence from given DNA template strand would be 3' CGCUGUAUGUGA-5' and will code for Arg-Cys-Met. Genetic code CGC codes for arginine, UGU for cysteine and AUG codes for methionine. UGA is a stop codon and terminates the process of protein synthesis. Thus, the correct answer is option B.