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Question

The given truth table is for

InputInputOutput
ABY
001
011
101
110

A
AND gate
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B
OR gate
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C
NAND gate
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D
NOR gate
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Solution

The correct option is C NAND gate
A NAND gate gives output as 1 when either of the input signals is low i.e. 0 and gives output as 0 only when both the input signals are high i.e. 1
Hence the above truth table is for NAND gate.

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