The gold number of haemoglobin is 0.03. 100mL of gold sol will require how much haemoglobin so that gold is not coagulated by 10mL of 10% NaCl solution?

0.03mg

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30mg

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0.30mg

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3mg

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Solution

The correct option is C 0.30mg
Gold number $= 0.03$
Gold sol volume $= 100 m l$
Let the amount of hemoglobin required is $x m g$

Since the gold number is the amount in milligrams required to prevent the coagulation of 10 ml of gold sol by 1 ml of 10% NaCl.

$∴ \frac{x}{100} \times 10 = 0.03 =$ Gold number

$∴ x = 0.30 m g$

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