The graph above shows the amount of force applied to an initially stationary 20 kg curling rock over time. What is the velocity of the rock after the force has been applied to it?

1.25 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 m/s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 5 m/s
The area under the force-time graph gives the impulse.
$I m p u l s e = F o r c e \times T i m e = \frac{1}{2} \times 50 \times 4 = 100 N - s$
Also, $I m p u l s e = C h a n g e i n m o m e n t u m = Δ p$
Since initially the rock was at rest, the impulse is given by the final impulse.
$I m p u l s e = m v 100 = 20 \times v V e l o c i t y = \frac{100}{20} m / s = 5 m / s$

Suggest Corrections

Similar questions

Q. A 6.0 N horizontal force is applied to a flat rock on a frictional frozen pond. causing it to accelerate at

2.0 m / s^{2}

. What is the mass of the rock?

An object of mass 50 kg has an initial velocity of $10 m / s$ . A force is applied on the object producing an acceleration of $2~ m/ $s^2$$ . what is the force applied on the object?

Q. A machine applied a force of

100 N

to move a rock. How far is the rock moved if the work done by the machine is

1250 J

An object has a initial velocity of $10 m s^{- 1}$ and acceleration of $2 m s^{- 2}$ . What is the net force applied by the engine to the car of mass $50 k g$ ?

Q. A body of mass 10 kg is moving with a velocity of 20 m/s. A force is applied to it so that in 10 s it acquires a velocity of 40 m/s. The force applied is:

Join BYJU'S Learning Program

The graph above shows the amount of force applied to an initially stationary 20 kg curling rock over time. What is the velocity of the rock after the force has been applied to it?

The correct option is B 5 m/sThe area under the force-time graph gives the impulse.Impulse=Force×Time=12×50×4=100N−sAlso, Impulse=Changeinmomentum=ΔpSince initially the rock was at rest, the impulse is given by the final impulse.Impulse=mv100=20×vVelocity=10020m/s=5m/s